You have a lot of possibilities to measure the temperature with an arduino. One simple solution is the usage of a KTY81 silicon temperature sensors.
Arduino describes on the playground the usage of KTY81-110. If you have an other type, you need to recalculate the temperature.
(Vcc 5+)--+-->2.7k--+-->kty81-210-->(GND)
| |
+->100nF--+-----> ADC2 (Analog Port 2)
Here is my code to use KTY81-210 with the arduino:
// resistor value of voltage divider in ohm
float resistor = 2700;
void setup() {
Serial.begin(9600);
}
void loop() {
float temp = kty(2);
Serial.print("Temperature: ");
Serial.println(temp,1);
delay (5000);
}
float kty(unsigned int port) {
float sensorValue = analogRead(port);
float resistance = sensorValue / (1023-sensorValue) * resistor;
// resistor values from kty81-210 data sheet, written as polynomial trend line
return -1.332e-11 * pow(resistance,4) + 6.621e-8 * pow(resistance,3) - 0.0002 * pow(resistance,2) + 0.2947 * resistance - 230.55;
}
11 replies on “Arduino and KTY81-210”
Hi! Thx for your code. In case you are still using this code: There happened a mistake in
float res_typ210[] = {980,1030,1135,1247,1367,1495,1630,1772,1922,2000,2080,2245,2417,2597,2785,2980,3192,3392,3607,3817,2915,4008,4166,4280};
the 4th value, counting from the end, should be 3915,
Thank you. I have changed the code.
Hi. I am compiling this code with latest Arduino 1.6.7 IDE on Arduino Uno R3 and i get following error:
Arduino: 1.6.7 (Windows 10), Board: “Arduino/Genuino Uno”
C:UsersUserDocumentsArduinotempSensortempSensor.ino: In function ‘float kty(unsigned int)’:
tempSensor:41: error: unable to find a register to spill in class ‘POINTER_REGS’
}
^
tempSensor:41: error: this is the insn:
(insn 57 56 59 3 (set (reg:SF 71 [ D.4034 ])
(mem:SF (post_inc:HI (reg:HI 8 r8 [orig:84 ivtmp.16 ] [84])) [2 MEM[base: _44, offset: 0B]+0 S4 A8])) C:UsersUserDocumentsArduinotempSensortempSensor.ino:33 99 {*movsf}
(expr_list:REG_INC (reg:HI 8 r8 [orig:84 ivtmp.16 ] [84])
(nil)))
C:UsersUserDocumentsArduinotempSensortempSensor.ino:41: confused by earlier errors, bailing out
exit status 1
unable to find a register to spill in class ‘POINTER_REGS’
if i comment this line, it compiles ok:
temp = map(resistance,res_typ210[i-1],res_typ210[i],temperature[i-1],temperature[i]);
any idea?
Thank you, for the comment.
I have simplified my code and replace the linear regression with a polynomial trend function.
Now the code is easier and use less memory.
Hello
Thx for the code, it’s helpfull in some ways.
I’m fairly new to arduino and have a question.
Is there any way to make it (much) more precise? I’m making a thermostat and, and want to read the temperature to 0.1°C precision. I’m also using an KTY81-210 I was thinking about an equation, but don’t know how to implement that into a function. Do you have any suggestions/tips?
The resolution of arduino is not fine enough. The A/D converter can only read 1024 different voltages. see: https://www.arduino.cc/en/Reference/AnalogRead
If you use a voltage divider with a suitable resistor you can read a temperature range with a higher resolution.
Hey,
Did similar recalculations, but just reduced huge and nano numbers in recalculations. After the tests the results are more precise, here is my code:
{code}
float kty(unsigned int port) {
// resistor value of voltage divider in ohm
float resistor = 2.7;
float sensorValue = analogRead(0);
float resistance = sensorValue / (1023.0 – sensorValue) * resistor;
return 0.4616 * pow(resistance,6) – 6.8569 * pow(resistance,5) + 41.072 * pow(resistance,4) – 124.4 * pow(resistance,3) + 187.43 * pow(resistance,2) – 47.345 * resistance – 102.0;
}
{code}
Hi, I’m somehow struggle with the polynomial trend.
when I use the function above with a kty81-210 connected as described I receive negative temperature values of ~-140°C instead of the room temperature (~25°C). Can you explain this function a little bit more in detail?
// resistor value of voltage divider in ohm
float resistor = 2700;
void setup() {
Serial.begin(9600);
}
void loop() {
float temp = kty(2);
Serial.print(“Temperature: “);
Serial.println(temp,1);
delay (500);
}
float kty(unsigned int port) {
float sensorValue = analogRead(A2);
float resistance = (resistor * sensorValue) / (1023-sensorValue);
// resistor values from kty81-210 data sheet, written as polynomial trend line
float R25 = 2000;
// We are also given alpha and beta
float alpha = 7.88 / 1000;
float beta = 1.937 / 10000;
// Now we need to calculate the temperature factor (KayTee)
float KayTee = resistance / R25;
// We now have all the information to calculate the actual temperature
// (AcT)
// Just hope I’ve got my brackets is the correct place!
return 25 + ((sqrt((alpha * alpha) – (4 * beta) + (4 * beta * KayTee)) – alpha) / (2 * beta));
//
}
Hi, I’m doing a little project with PTC already installed in a system, with a characteristic similar to a kty81-120, I’m not a skilled electronic or mathematic, I’m looking for the calculation for that one:
// resistor values from kty81-210 data sheet, written as polynomial trend line
return -1.332e-11 * pow(resistance,4) + 6.621e-8 * pow(resistance,3) – 0.0002 * pow(resistance,2) + 0.2947 * resistance – 230.55;
Can you help me?
hye can assist me how to recalculate the polynomial trend line for kty 83-122. Thanks you